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  • a^b(位运算&快速幂)

    题目链接

    题目:

     题解:很简单、经典的的一道快速幂的题 注意一下用LL型就ok。

    代码:

     1 #include <map>
     2 #include <set>
     3 #include <list>
     4 #include <stack>
     5 #include <queue>
     6 #include <deque>
     7 #include <cmath>
     8 #include <ctime>
     9 #include <string>
    10 #include <limits>
    11 #include <cstdio>
    12 #include <vector>
    13 #include <iomanip>
    14 #include <cstdlib>
    15 #include <cstring>
    16 #include <istream>
    17 #include <iostream>
    18 #include <algorithm>
    19 #define ci cin
    20 #define co cout
    21 #define el endl
    22 #define Scc(c) scanf("%c",&c)
    23 #define Scs(s) scanf("%s",s)
    24 #define Sci(x) scanf("%d",&x)
    25 #define Sci2(x, y) scanf("%d%d",&x,&y)
    26 #define Sci3(x, y, z) scanf("%d%d%d",&x,&y,&z)
    27 #define Scl(x) scanf("%I64d",&x)
    28 #define Scl2(x, y) scanf("%I64d%I64d",&x,&y)
    29 #define Scl3(x, y, z) scanf("%I64d%I64d%I64d",&x,&y,&z)
    30 #define Pri(x) printf("%d
    ",x)
    31 #define Prl(x) printf("%I64d
    ",x)
    32 #define Prc(c) printf("%c
    ",c)
    33 #define Prs(s) printf("%s
    ",s)
    34 #define For(i,x,y) for(int i=x;i<y;i++)
    35 #define For_(i,x,y) for(int i=x;i<=y;i++)
    36 #define FFor(i,x,y) for(int i=x;i>y;i--)
    37 #define FFor_(i,x,y) for(int i=x;i>=y;i--)
    38 #define Mem(f, x) memset(f,x,sizeof(f))
    39 #define LL long long
    40 #define ULL unsigned long long
    41 #define MAXSIZE 100005
    42 #define INF 0x3f3f3f3f
    43 
    44 LL mod;
    45 const double PI = acos(-1.0);
    46 
    47 using namespace std;
    48 void power(LL a,LL b)
    49 {
    50     LL ans=1%mod;
    51     while(b)
    52     {
    53         if(b&1)
    54             ans=a*1ll*ans%mod;
    55         a=a*1ll*a%mod;
    56         b>>=1;
    57     }
    58     cout << ans;
    59 }
    60 int main()
    61 {
    62     int a,b;
    63     cin>>a>>b>>mod;
    64     power(a,b);
    65     return 0;
    66 }
    View Code
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  • 原文地址:https://www.cnblogs.com/hbhdhd/p/13191349.html
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