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  • 100. Same Tree

    Given two binary trees, write a function to check if they are equal or not.

    Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *     int val;
     *     TreeNode left;
     *     TreeNode right;
     *     TreeNode(int x) { val = x; }
     * }
     */
    class Pair{
        TreeNode x;
        TreeNode y;
        public Pair(TreeNode x, TreeNode y){
            this.x = x;
            this.y = y;
        }
    }
    public class Solution {
        //recursive
        // public boolean isSameTree(TreeNode p, TreeNode q) {
        //     if(p == null && q == null)
        //         return true;
        //     if(p == null || q== null || p.val != q.val)
        //         return false;
        //     return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
        // }
        
        public boolean isSameTree(TreeNode p, TreeNode q) {
            if(p == null && q == null)
                return true;
            if(p == null || q== null || p.val != q.val)
                return false;
            Queue<Pair> queue = new LinkedList<Pair>();
            queue.offer(new Pair(p, q));
            while(!queue.isEmpty()){
                Pair values = queue.poll();
                if(values.x  == null && values.y == null)
                    continue;
                if(values.x != null && values.y != null){
                    queue.offer(new Pair(values.x.left, values.y.left));
                    queue.offer(new Pair(values.x.right, values.y.right));
                }
                if(values.x == null || values.y == null || values.x.val != values.y.val) return false;
            }
            return true;
        }
    }
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  • 原文地址:https://www.cnblogs.com/joannacode/p/5998959.html
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